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FormatCode Code Formatter is based on serveral powerful syntax parser engines
so you can exactly control the appearance of your source code. Here is the code formatting demo of
FormatCode C/C++ Code Formatter to prove the ability of code formatting
functions of FormatCode:
X=1024; Y=768; A=3;
J=0;K=-10;L=-7;M=1296;N=36;O=255;P=9;_=1<<15;E;S;C;D;F(b){E="1""111886:6:??AAF"
"FHHMMOO55557799@@>>>BBBGGIIKK"[b]-64;C="C@=::C@@==@=:C@=:C@=:C5""31/513/5131/"
"31/531/53"[b ]-64;S=b<22?9:0;D=2;}I(x,Y,X){Y?(X^=Y,X*X>x?(X^=Y):0, I (x,Y/2,X
)):(E=X); }H(x){I(x, _,0);}p;q( c,x,y,z,k,l,m,a, b){F(c
);x-=E*M ;y-=S*M ;z-=C*M ;b=x* x/M+ y*y/M+z
*z/M-D*D *M;a=-x *k/M -y*l/M-z *m/M; p=((b=a*a/M-
b)>=0?(I (b*M,_ ,0),b =E, a+(a>b ?-b:b)): -1.0);}Z;W;o
(c,x,y, z,k,l, m,a){Z=! c? -1:Z;c <44?(q(c,x ,y,z,k,
l,m,0,0 ),(p> 0&&c!= a&& (p<W ||Z<0) )?(W=
p,Z=c): 0,o(c+ 1, x,y,z, k,l, m,a)):0 ;}Q;T;
U;u;v;w ;n(e,f,g, h,i,j,d,a, b,V){o(0 ,e,f,g,h,i,j,a);d>0
&&Z>=0? (e+=h*W/M,f+=i*W/M,g+=j*W/M,F(Z),u=e-E*M,v=f-S*M,w=g-C*M,b=(-2*u-2*v+w)
/3,H(u*u+v*v+w*w),b/=D,b*=b,b*=200,b/=(M*M),V=Z,E!=0?(u=-u*M/E,v=-v*M/E,w=-w*M/
E):0,E=(h*u+i*v+j*w)/M,h-=u*E/(M/2),i-=v*E/(M/2),j-=w*E/(M/2),n(e,f,g,h,i,j,d-1
,Z,0,0),Q/=2,T/=2, U/=2,V=V<22?7: (V<30?1:(V<38?2:(V<44?4:(V==44?6:3))))
,Q+=V&1?b:0,T +=V&2?b :0,U+=V &4?b:0) :(d==P?(g+=2
,j=g>0?g/8:g/ 20):0,j >0?(U= j *j/M,Q =255- 250*U/M,T=255
-150*U/M,U=255 -100 *U/M):(U =j*j /M,U<M /5?(Q=255-210*U
/M,T=255-435*U /M,U=255 -720* U/M):(U -=M/5,Q=213-110*U
/M,T=168-113*U / M,U=111 -85*U/M) ),d!=P?(Q/=2,T/=2
,U/=2):0);Q=Q< 0?0: Q>O? O: Q;T=T<0? 0:T>O?O:T;U=U<0?0:
U>O?O:U;}R;G;B ;t(x,y ,a, b){n(M*J+M *40*(A*x +a)/X/A-M*20,M*K,M
*L-M*30*(A*y+b)/Y/A+M*15,0,M,0,P, -1,0,0);R+=Q ;G+=T;B +=U;++a<A?t(x,y,a,
b):(++b<A?t(x,y,0,b):0);}r(x,y){R=G=B=0;t(x,y,0,0);x<X?(printf("%c%c%c",R/A/A,G
/A/A,B/A/A),r(x+1,y)):0;}s(y){r(0,--y?s(y),y:y);}main(){printf("P6\n%i %i\n255"
"\n",X,Y);s(Y);}
X = 1024;
Y = 768;
A = 3;
J = 0;
K = -10;
L = -7;
M = 1296;
N = 36;
O = 255;
P = 9;
_ = 1 << 15;
E;
S;
C;
D;
F(b)
{
E = "1""111886:6:??AAF""FHHMMOO55557799@@>>>BBBGGIIKK"[b] - 64;
C = "C@=::C@@==@=:C@=:C@=:C5""31/513/5131/""31/531/53"[b] - 64;
S = b < 22 ? 9 : 0;
D = 2;
}
I(x, Y, X)
{
Y ? (X ^= Y, X *X > x ? (X ^= Y) : 0, I(x, Y / 2, X)) : (E = X);
}
H(x)
{
I(x, _, 0);
}
p;
q(c, x, y, z, k, l, m, a, b)
{
F(c);
x -= E * M;
y -= S * M;
z -= C * M;
b = x * x / M + y * y / M + z*z / M - D * D * M;
a = - x * k / M - y * l / M - z * m / M;
p = ((b = a * a / M - b) >= 0 ? (I(b *M, _, 0), b = E, a + (a > b ? - b: b))
: - 1.0);
}
Z;
W;
o(c, x, y, z, k, l, m, a)
{
Z = !c ? -1: Z;
c < 44 ? (q(c, x, y, z, k, l, m, 0, 0), (p > 0 && c != a && (p < W || Z < 0))
? (W = p, Z = c): 0, o(c + 1, x, y, z, k, l, m, a)): 0;
}
Q;
T;
U;
u;
v;
w;
n(e, f, g, h, i, j, d, a, b, V)
{
o(0, e, f, g, h, i, j, a);
d > 0 && Z >= 0 ? (e += h * W / M, f += i * W / M, g += j * W / M, F(Z), u =
e-E * M, v = f - S * M, w = g - C * M, b = ( - 2 * u - 2 *
v + w) / 3, H(u *u + v * v + w * w), b /= D, b *= b, b *=
200, b /= (M *M), V = Z, E != 0 ? (u = - u * M / E, v =
- v * M / E, w = - w * M / E): 0, E = (h *u + i * v + j *
w) / M, h -= u * E / (M / 2), i -= v * E / (M / 2), j -= w
* E / (M / 2), n(e, f, g, h, i, j, d - 1, Z, 0, 0), Q /= 2,
T /= 2, U /= 2, V = V < 22 ? 7 : (V < 30 ? 1 : (V < 38 ? 2
: (V < 44 ? 4 : (V == 44 ? 6 : 3)))), Q += V &1 ? b : 0, T
+= V &2 ? b : 0, U += V &4 ? b : 0): (d == P ? (g += 2, j
= g > 0 ? g / 8: g / 20): 0, j > 0 ? (U = j * j / M, Q =
255-250 * U / M, T = 255 - 150 * U / M, U = 255-100 * U /
M): (U = j * j / M, U < M / 5 ? (Q = 255-210 * U / M, T =
255-435 * U / M, U = 255-720 * U / M): (U -= M / 5, Q =
213-110 * U / M, T = 168-113 * U / M, U = 111-85 * U / M)),
d != P ? (Q /= 2, T /= 2, U /= 2): 0);
Q = Q < 0 ? 0 : Q > O ? O : Q;
T = T < 0 ? 0 : T > O ? O : T;
U = U < 0 ? 0 : U > O ? O : U;
}
R;
G;
B;
t(x, y, a, b)
{
n(M * J + M * 40 *(A * x + a) / X / A - M * 20, M * K, M * L - M * 30 *(A *
y + b) / Y / A + M * 15, 0, M, 0, P, - 1, 0, 0);
R += Q;
G += T;
B += U;
++a < A ? t(x, y, a, b): (++b < A ? t(x, y, 0, b): 0);
}
r(x, y)
{
R = G = B = 0;
t(x, y, 0, 0);
x < X ? (printf("%c%c%c", R / A / A, G / A / A, B / A / A), r(x + 1, y)): 0;
}
s(y)
{
r(0, --y ? s(y), y: y);
}
main()
{
printf("P6\n%i %i\n255""\n", X, Y);
s(Y);
}
This C source code is come from IOCCC, the International Obfuscated C Code Contest.
Click here to preview the C/C++ Code Formatting Demo 2, C/C++ Code Formatting Demo 3 and C/C++ Code Formatting Demo 4.
 With FormatCode C++ Code Formatters, you can format and transform any foreign C/C++ source code to meet your preferred coding style or any common code convention in several seconds!
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